What is x+y=2,8x-3y=8 ?

The solution to x+y=2,8x-3y=8 is x= 14/11 ,y= 8/11

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x+y=2,8x-3y=8

x + y = 2, 8 x - 3 y = 8

x = \frac{14}{11}, y = \frac{8}{11}

Solution steps

[x + y = 2 8 x - 3 y = 8]

Isolate

x

for

x + y = 2 : x = 2 - y

Substitute

x = 2 - y

[8 (2 - y) - 3 y = 8]

Simplify

[16 - 11 y = 8]

Isolate

y

for

16 - 11 y = 8 : y = \frac{8}{11}

For

x = 2 - y

Substitute

y = \frac{8}{11}

x = 2 - \frac{8}{11}

2 - \frac{8}{11} = \frac{14}{11}

x = \frac{14}{11}

The solutions to the system of equations are:

x = \frac{14}{11}, y = \frac{8}{11}

5 x - y = - 3, 4 x - y = - 5

3 x + 8 y = 89, - 5 x - 2 y = - 1

\frac{x}{5} - \frac{y}{2} = 1, 0.32 x - y = 1

2 x - 4 y = 8, x + 8 y = 4

2 x - y = 3, 4 x - y = 5