What is 20a+9b=63,15a+4b=39 ?

The solution to 20a+9b=63,15a+4b=39 is a= 9/5 ,b=3

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20a+9b=63,15a+4b=39

20 a + 9 b = 63, 15 a + 4 b = 39

a = \frac{9}{5}, b = 3

Solution steps

[20 a + 9 b = 63 15 a + 4 b = 39]

Isolate

a

for

20 a + 9 b = 63 : a = \frac{63 - 9 b}{20}

Substitute

a = \frac{63 - 9 b}{20}

[15 \cdot \frac{63 - 9 b}{20} + 4 b = 39]

Simplify

[\frac{- 11 b + 189}{4} = 39]

Isolate

b

for

\frac{- 11 b + 189}{4} = 39 : b = 3

For

a = \frac{63 - 9 b}{20}

Substitute

b = 3

a = \frac{63 - 9 \cdot 3}{20}

\frac{63 - 9 \cdot 3}{20} = \frac{9}{5}

a = \frac{9}{5}

The solutions to the system of equations are:

a = \frac{9}{5}, b = 3

9 x + 3 y + 12 = 6, x - 3 y + 10 = 0

10 x - 3 y = 36, 2 x + 5 y = - 4

x = 2 t, y = 4 t^{3} - 1

x - y = 4, x + y = 5

\frac{x}{4 - 3} = \frac{y}{6}, \frac{1}{2} x - y = - 2

What is 20a+9b=63,15a+4b=39 ?
The solution to 20a+9b=63,15a+4b=39 is a= 9/5 ,b=3