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Popular >

f(x)=x^3+1,x^0=1

Solution

f (x) = x^{3} + 1, x^{0} = 1

Solution

2

Solution steps

Find

f \circ x^{0}

given

f (x) = x^{3} + 1, x^{0} = 1

f \circ x^{0} = f ((x^{0}) (x))

(x^{0}) (x) : 1

= f (1)

f (1) : 2

= 2

Popular Examples

3y-x=5,2y+x=-10

3 y - x = 5, 2 y + x = - 10

x+y+z=1,2x-2y+z=3,-3x+y+2z=0

x + y + z = 1, 2 x - 2 y + z = 3, - 3 x + y + 2 z = 0

1/2*x+1/3*y=3,x+1/2*y=5

\frac{1}{2} \cdot x + \frac{1}{3} \cdot y = 3, x + \frac{1}{2} \cdot y = 5

-1/8*x+y= 33/4 ,-1/9*x-1/10*y=-47/30

- \frac{1}{8} \cdot x + y = \frac{33}{4}, - \frac{1}{9} \cdot x - \frac{1}{10} \cdot y = - \frac{47}{30}

9x+3y=33,3x+9y=51

9 x + 3 y = 33, 3 x + 9 y = 51

Frequently Asked Questions (FAQ)

What is the f(x)=x^3+1,x^0=1 ?
The f(x)=x^3+1,x^0=1 is 2