What is ((x+y))/((x-y))=-7,((x+y+1))/((x+y-1))= 3/4 ?

The solution to ((x+y))/((x-y))=-7,((x+y+1))/((x+y-1))= 3/4 is

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((x+y))/((x-y))=-7,((x+y+1))/((x+y-1))= 3/4

\frac{( x + y )}{( x - y )} = - 7, \frac{( x + y + 1 )}{( x + y - 1 )} = \frac{3}{4}

(x = - 3, y = - 4)

Solution steps

[\frac{( x + y )}{( x - y )} = - 7 \frac{( x + y + 1 )}{( x + y - 1 )} = \frac{3}{4}]

Isolate

x

for

\frac{( x + y )}{( x - y )} = - 7 : x = \frac{3 y}{4}

Plug the solutions

x = \frac{3 y}{4}

into

\frac{( x + y + 1 )}{( x + y - 1 )} = \frac{3}{4}

For

\frac{( x + y + 1 )}{( x + y - 1 )} = \frac{3}{4}

, subsitute

x

with

\frac{3 y}{4} : y = - 4

Plug the solutions

y = - 4

into

\frac{( x + y )}{( x - y )} = - 7

For

\frac{( x + y )}{( x - y )} = - 7

, subsitute

y

with

- 4 : x = - 3

Verify solutions by plugging them into the original equations

Therefore, the final solution for

\frac{( x + y )}{( x - y )} = - 7, \frac{( x + y + 1 )}{( x + y - 1 )} = \frac{3}{4}

(x = - 3, y = - 4)

1 x - 2 y = 5, 2 x + 3 y = 24

5 x - y = 7, 3 x + 2 y = 12

2 x - 3 y = 5, 5 x + 7 y = - 2

3 x - 4 y = 26, 2 x - 3 y = - 19

x - y = 1, - x + 2 y = 3

What is ((x+y))/((x-y))=-7,((x+y+1))/((x+y-1))= 3/4 ?
The solution to ((x+y))/((x-y))=-7,((x+y+1))/((x+y-1))= 3/4 is