What is 2x-3y=15,3x+3y=40 ?

The solution to 2x-3y=15,3x+3y=40 is x=11,y= 7/3

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2x-3y=15,3x+3y=40

2 x - 3 y = 15, 3 x + 3 y = 40

x = 11, y = \frac{7}{3}

Solution steps

[2 x - 3 y = 15 3 x + 3 y = 40]

Isolate

x

for

2 x - 3 y = 15 : x = \frac{15 + 3 y}{2}

Substitute

x = \frac{15 + 3 y}{2}

[3 \cdot \frac{15 + 3 y}{2} + 3 y = 40]

Simplify

[\frac{45 + 15 y}{2} = 40]

Isolate

y

for

\frac{45 + 15 y}{2} = 40 : y = \frac{7}{3}

For

x = \frac{15 + 3 y}{2}

Substitute

y = \frac{7}{3}

x = \frac{15 + 3 \cdot \frac{7}{3}}{2}

\frac{15 + 3 \cdot \frac{7}{3}}{2} = 11

x = 11

The solutions to the system of equations are:

x = 11, y = \frac{7}{3}

5 y + 3 x = 7, 4 x - 2 y = - 8

x + 3 y = 6, x - y = 2

4 x + 3 y = - 2.5, 5 x + 2 y = 10

17 x + 10 y = 61, 5 x + 10 y = 4

2 x + y + z = 7, x - y - z = - 4, 3 x + 2 y + z = 10