What is y13=1,z13=10,0.03+j0.09=3.33-j10 ?

The solution to y13=1,z13=10,0.03+j0.09=3.33-j10 is y= 1/13 ,j= 330/1009 ,z= 10/13

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y13=1,z13=10,0.03+j0.09=3.33-j10

y 13 = 1, z 13 = 10, 0.03 + j 0.09 = 3.33 - j 10

y = \frac{1}{13}, j = \frac{330}{1009}, z = \frac{10}{13}

Solution steps

y \cdot 13 = 1 z \cdot 13 = 10 0.03 + j \cdot 0.09 = 3.33 - j \cdot 10

Isolate

y

for

y 13 = 1 : y = \frac{1}{13}

[z \cdot 13 = 10 0.03 + j \cdot 0.09 = 3.33 - j \cdot 10]

Isolate

z

for

z 13 = 10 : z = \frac{10}{13}

[0.03 + j \cdot 0.09 = 3.33 - j \cdot 10]

Isolate

j

for

0.03 + j 0.09 = 3.33 - j 10 : j = \frac{330}{1009}

The solutions to the system of equations are:

y = \frac{1}{13}, j = \frac{330}{1009}, z = \frac{10}{13}

- 2 x + 3 y = 7, x + 7 y = 5

3 x + y = 2, 7 x - 2 y = 2

a = - 18, a^{5} = 9, a^{9} = 0

3 x + 5 y = 8, 7 x - 9 y = 7

x + 2 y = - 4, 3 x - 2 y = 20

What is y13=1,z13=10,0.03+j0.09=3.33-j10 ?
The solution to y13=1,z13=10,0.03+j0.09=3.33-j10 is y= 1/13 ,j= 330/1009 ,z= 10/13