What are the solutions to the equation 6^2+x^2=12^2 ?

The solutions to the equation 6^2+x^2=12^2 are x=6sqrt(3),x=-6sqrt(3)

Find the zeros of 6^2+x^2=12^2

The zeros of 6^2+x^2=12^2 are x=6sqrt(3),x=-6sqrt(3)

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6^{2} + x^{2} = 1 2^{2}

x = 63, x = - 63

Solution steps

6^{2} + x^{2} = 1 2^{2}

Move

6^{2}

to the right side

x^{2} = 108

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 108, x = - 108

108 = 63

- 108 = - 63

x = 63, x = - 63

2 x + x - 1 \geq 0

\frac{3 x + 1}{4} - \frac{1}{3} \leq \frac{2}{15} (3 x + 2) + \frac{4 ( 1 - x )}{3}

- 2 - 3 n = - 56

\frac{x + 1}{3 - x} > 2

1 > \frac{- 7 x + 3}{4} \geq - 6

What are the solutions to the equation 6^2+x^2=12^2 ?
The solutions to the equation 6^2+x^2=12^2 are x=6sqrt(3),x=-6sqrt(3)
Find the zeros of 6^2+x^2=12^2
The zeros of 6^2+x^2=12^2 are x=6sqrt(3),x=-6sqrt(3)