What is x/(10)+y/5-1=0, x/8+y/6 =2 ?

The solution to x/(10)+y/5-1=0, x/8+y/6 =2 is x=28,y=-9

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x/(10)+y/5-1=0, x/8+y/6 =2

\frac{x}{10} + \frac{y}{5} - 1 = 0, \frac{x}{8} + \frac{y}{6} = 2

x = 28, y = - 9

Solution steps

[\frac{x}{10} + \frac{y}{5} - 1 = 0 \frac{x}{8} + \frac{y}{6} = 2]

Isolate

x

for

\frac{x}{10} + \frac{y}{5} - 1 = 0 : x = - 2 y + 10

Substitute

x = - 2 y + 10

[\frac{- 2 y + 10}{8} + \frac{y}{6} = 2]

Simplify

[\frac{- y + 15}{12} = 2]

Isolate

y

for

\frac{- y + 15}{12} = 2 : y = - 9

For

x = - 2 y + 10

Substitute

y = - 9

x = - 2 (- 9) + 10

- 2 (- 9) + 10 = 28

x = 28

The solutions to the system of equations are:

x = 28, y = - 9

2 x + 3 y = 9, - x + y = - 2

2 x - y = 0, x + y = 15

8^{x} = 2^{y + 1}, 5^{y} = 2 5^{x + 1}

5 x_{1} + 7 x_{2} = 3, 2 x_{1} + 4 x_{2} = 1

2 y - x = - 9, 7 y - 2 x = 3

What is x/(10)+y/5-1=0, x/8+y/6 =2 ?
The solution to x/(10)+y/5-1=0, x/8+y/6 =2 is x=28,y=-9