What is 2x+x-y/6 =2,x-2x+y/3 =1 ?

The solution to 2x+x-y/6 =2,x-2x+y/3 =1 is x=1,y=6

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2x+x-y/6 =2,x-2x+y/3 =1

2 x + x - \frac{y}{6} = 2, x - 2 x + \frac{y}{3} = 1

x = 1, y = 6

Solution steps

[2 x + x - \frac{y}{6} = 2 x - 2 x + \frac{y}{3} = 1]

Isolate

x

for

2 x + x - \frac{y}{6} = 2 : x = \frac{12 + y}{18}

Substitute

x = \frac{12 + y}{18}

[\frac{12 + y}{18} - 2 \cdot \frac{12 + y}{18} + \frac{y}{3} = 1]

Simplify

[\frac{- 12 + 5 y}{18} = 1]

Isolate

y

for

\frac{- 12 + 5 y}{18} = 1 : y = 6

For

x = \frac{12 + y}{18}

Substitute

y = 6

x = \frac{12 + 6}{18}

Simplify

x = 1

The solutions to the system of equations are:

x = 1, y = 6

y = \frac{( 23 x )}{4}, x = - 8

141 x + 93 y = 18, 993 x + 141 y = 45

- x + 4 y = 11, 2 x + y = - 4

\frac{x}{2} + \frac{y}{3} = 2, \frac{x}{3} + \frac{y}{9} = 1

x + y = 3, 3 x - 2 y = 5

What is 2x+x-y/6 =2,x-2x+y/3 =1 ?
The solution to 2x+x-y/6 =2,x-2x+y/3 =1 is x=1,y=6