What is 1/x-1/((y-2))=-1, d/x+3/((y-2))=5 ?

The solution to 1/x-1/((y-2))=-1, d/x+3/((y-2))=5 is

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1/x-1/((y-2))=-1, d/x+3/((y-2))=5

\frac{1}{x} - \frac{1}{( y - 2 )} = - 1, \frac{d}{x} + \frac{3}{( y - 2 )} = 5

(x = - \frac{- d - 3}{2}, y = \frac{3 d + 13}{d + 5})

Solution steps

[\frac{1}{x} - \frac{1}{( y - 2 )} = - 1 \frac{d}{x} + \frac{3}{( y - 2 )} = 5]

Isolate

x

for

\frac{1}{x} - \frac{1}{( y - 2 )} = - 1 : x = \frac{- y + 2}{y - 3}; y \neq = 3

Plug the solutions

x = \frac{- y + 2}{y - 3}

into

\frac{d}{x} + \frac{3}{( y - 2 )} = 5

For

\frac{d}{x} + \frac{3}{( y - 2 )} = 5

, subsitute

x

with

\frac{- y + 2}{y - 3} : y = \frac{3 d + 13}{d + 5}; d \neq = - 5

Plug the solutions

y = \frac{3 d + 13}{d + 5}

into

\frac{1}{x} - \frac{1}{( y - 2 )} = - 1

For

\frac{1}{x} - \frac{1}{( y - 2 )} = - 1

, subsitute

y

with

\frac{3 d + 13}{d + 5} : x = - \frac{- d - 3}{2}; d \neq = - 5

Verify solutions by plugging them into the original equations

Therefore, the final solution for

\frac{1}{x} - \frac{1}{( y - 2 )} = - 1, \frac{d}{x} + \frac{3}{( y - 2 )} = 5

(x = - \frac{- d - 3}{2}, y = \frac{3 d + 13}{d + 5})

3 x - 4 y = 11, 2 x + 8 y = - 14

4 x + y = 8, 8 x + 13 y = 2

y = 2 x + 3, y = x + 1

11 x - 3 y = 69, - 3 x + 3 y = 3

12 x - 16 y = - 2, 4 y^{8} x + 16 y = 64

What is 1/x-1/((y-2))=-1, d/x+3/((y-2))=5 ?
The solution to 1/x-1/((y-2))=-1, d/x+3/((y-2))=5 is