What are the solutions to the equation x^2-3x+4=0 ?

The solutions to the equation x^2-3x+4=0 are x= 3/2+i(sqrt(7))/2 ,x= 3/2-i(sqrt(7))/2

Find the zeros of x^2-3x+4=0

The zeros of x^2-3x+4=0 are x= 3/2+i(sqrt(7))/2 ,x= 3/2-i(sqrt(7))/2

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x^{2} - 3 x + 4 = 0

x = \frac{3}{2} + i \frac{7}{2}, x = \frac{3}{2} - i \frac{7}{2}

Solution steps

x^{2} - 3 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

(- 3)^{2} - 4 \cdot 1 \cdot 4 : 7 i

x_{1, 2} = \frac{- ( - 3 ) \pm 7 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 7 i}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 7 i}{2 \cdot 1}

x = \frac{- ( - 3 ) + 7 i}{2 \cdot 1} : \frac{3}{2} + i \frac{7}{2}

x = \frac{- ( - 3 ) - 7 i}{2 \cdot 1} : \frac{3}{2} - i \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{7}{2}, x = \frac{3}{2} - i \frac{7}{2}

x^{2} + 14 x + 33 \geq 0

19 x^{4} - 19

(2 - 7)^{2}

k^{2} - 16 k + 64 = 0

What are the solutions to the equation x^2-3x+4=0 ?
The solutions to the equation x^2-3x+4=0 are x= 3/2+i(sqrt(7))/2 ,x= 3/2-i(sqrt(7))/2
Find the zeros of x^2-3x+4=0
The zeros of x^2-3x+4=0 are x= 3/2+i(sqrt(7))/2 ,x= 3/2-i(sqrt(7))/2