What is x-4=4,(y+2)3(x-2)+2y=20 ?

The solution to x-4=4,(y+2)3(x-2)+2y=20 is

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x-4=4,(y+2)3(x-2)+2y=20

x - 4 = 4, (y + 2) 3 (x - 2) + 2 y = 20

(x = 8, y = - \frac{4}{5})

Solution steps

[x - 4 = 4 (y + 2) \cdot 3 (x - 2) + 2 y = 20]

Solve

x - 4 = 4 : x = 8

Plug the solutions

x = 8

into

(y + 2) 3 (x - 2) + 2 y = 20

For

(y + 2) 3 (x - 2) + 2 y = 20

, subsitute

x

with

8 : y = - \frac{4}{5}

Verify solutions by plugging them into the original equations

Therefore, the final solution for

x - 4 = 4, (y + 2) 3 (x - 2) + 2 y = 20

(x = 8, y = - \frac{4}{5})

+ y x + y = 6, x = 2

\frac{x}{3} - \frac{4}{y} = 2, \frac{x}{4} + \frac{6}{y} = 6

3 a - 2 b = 0, - 19 - 9 b = - 65

2 x + y = 5, 2 x - y = 8

x + y + z = 11, x - y + 3 z = 13, 2 x + 2 y - z = 7