What are the solutions to the equation 4x^2+23x-6=0 ?

The solutions to the equation 4x^2+23x-6=0 are x= 1/4 ,x=-6

Find the zeros of 4x^2+23x-6=0

The zeros of 4x^2+23x-6=0 are x= 1/4 ,x=-6

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4 x^{2} + 23 x - 6 = 0

x = \frac{1}{4}, x = - 6

Decimal Notation

x = 0.25, x = - 6

Solution steps

4 x^{2} + 23 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 23 \pm 2 3 ^{2} - 4 \cdot 4 ( - 6 )}{2 \cdot 4}

2 3^{2} - 4 \cdot 4 (- 6) = 25

x_{1, 2} = \frac{- 23 \pm 25}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 23 + 25}{2 \cdot 4}, x_{2} = \frac{- 23 - 25}{2 \cdot 4}

x = \frac{- 23 + 25}{2 \cdot 4} : \frac{1}{4}

x = \frac{- 23 - 25}{2 \cdot 4} : - 6

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - 6

3 < 2 x + 1 \leq 9

x \leq 4 and x > - 4

x^{2} - 12 x + 35

2 (16)^{\frac{3}{4}}

45 x^{2} - 120 x y + 80 y^{2}

What are the solutions to the equation 4x^2+23x-6=0 ?
The solutions to the equation 4x^2+23x-6=0 are x= 1/4 ,x=-6
Find the zeros of 4x^2+23x-6=0
The zeros of 4x^2+23x-6=0 are x= 1/4 ,x=-6