What is 4x+3y=8,8x+9y=77 ?

The solution to 4x+3y=8,8x+9y=77 is x=-53/4 ,y= 61/3

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4x+3y=8,8x+9y=77

4 x + 3 y = 8, 8 x + 9 y = 77

x = - \frac{53}{4}, y = \frac{61}{3}

Solution steps

[4 x + 3 y = 8 8 x + 9 y = 77]

Isolate

x

for

4 x + 3 y = 8 : x = \frac{8 - 3 y}{4}

Substitute

x = \frac{8 - 3 y}{4}

[8 \cdot \frac{8 - 3 y}{4} + 9 y = 77]

Simplify

[3 y + 16 = 77]

Isolate

y

for

3 y + 16 = 77 : y = \frac{61}{3}

For

x = \frac{8 - 3 y}{4}

Substitute

y = \frac{61}{3}

x = \frac{8 - 3 \cdot \frac{61}{3}}{4}

\frac{8 - 3 \cdot \frac{61}{3}}{4} = - \frac{53}{4}

x = - \frac{53}{4}

The solutions to the system of equations are:

x = - \frac{53}{4}, y = \frac{61}{3}

3 x + 5 y = 0, 4 y = 2 x + 30

2 x + y = 7, 3 x + 2 y = 12

\frac{9}{x} + \frac{10}{y} = - 11, \frac{7}{x} - \frac{15}{y} = - 4

4 x + 2 y = 9, 8 x + 2 y = 14

x = \frac{17}{11}, z = \frac{4}{121}