What is y+1=2,(x-1)ey-1=x+1 ?

The solution to y+1=2,(x-1)ey-1=x+1 is

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y+1=2,(x-1)ey-1=x+1

y + 1 = 2, (x - 1) ey - 1 = x + 1

(x = \frac{2 + e}{e - 1}, y = 1)

Solution steps

[y + 1 = 2 (x - 1) ey - 1 = x + 1]

Solve

y + 1 = 2 : y = 1

Plug the solutions

y = 1

into

(x - 1) ey - 1 = x + 1

For

(x - 1) ey - 1 = x + 1

, subsitute

y

with

1 : x = \frac{2 + e}{e - 1}

Verify solutions by plugging them into the original equations

Therefore, the final solution for

y + 1 = 2, (x - 1) ey - 1 = x + 1

(x = \frac{2 + e}{e - 1}, y = 1)

3 x + y = 1, (2 k - 1) x + (k - 1) y = (2 k - 1)

2 x - y = 11, 5 x + 4 y = 1

u = (62), a = (3 - 9)

11 x - 9 y + 4 = 6, x - 5 y + 3 = 0

5 x - 6 y = 3, 8 x + 2 y = 28