What is 7x-4y=1,1-5+6y=0 ?

The solution to 7x-4y=1,1-5+6y=0 is x= 11/21 ,y= 2/3

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7x-4y=1,1-5+6y=0

7 x - 4 y = 1, 1 - 5 + 6 y = 0

x = \frac{11}{21}, y = \frac{2}{3}

Solution steps

[7 x - 4 y = 1 1 - 5 + 6 y = 0]

Isolate

y

for

1 - 5 + 6 y = 0 : y = \frac{2}{3}

Substitute

y = \frac{2}{3}

[7 x - 4 \cdot \frac{2}{3} = 1]

Simplify

[7 x - \frac{8}{3} = 1]

Isolate

x

for

7 x - \frac{8}{3} = 1 : x = \frac{11}{21}

The solutions to the system of equations are:

x = \frac{11}{21}, y = \frac{2}{3}

x + 3 y = 1, 3 y = x + 3

3 x + 8 y = 19, 4 x - y = 2

2 x + 4 y + z = 23, 6 x + 2 y - z = 35, 4 x - y + 2 z = 19

x - 3 y = 5, 7 x - 8 y = 6

5 x + 3 y = 35, 2 x + 4 y = 28