What is 3x-y-3/5 =6,3y-x-2/7 =9 ?

The solution to 3x-y-3/5 =6,3y-x-2/7 =9 is x= 509/140 ,y= 603/140

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3x-y-3/5 =6,3y-x-2/7 =9

3 x - y - \frac{3}{5} = 6, 3 y - x - \frac{2}{7} = 9

x = \frac{509}{140}, y = \frac{603}{140}

Solution steps

[3 x - y - \frac{3}{5} = 6 3 y - x - \frac{2}{7} = 9]

Isolate

x

for

3 x - y - \frac{3}{5} = 6 : x = \frac{5 y + 33}{15}

Substitute

x = \frac{5 y + 33}{15}

[3 y - \frac{5 y + 33}{15} - \frac{2}{7} = 9]

Simplify

[- \frac{2}{7} + \frac{40 y - 33}{15} = 9]

Isolate

y

for

- \frac{2}{7} + \frac{40 y - 33}{15} = 9 : y = \frac{603}{140}

For

x = \frac{5 y + 33}{15}

Substitute

y = \frac{603}{140}

x = \frac{5 \cdot \frac{603}{140} + 33}{15}

\frac{5 \cdot \frac{603}{140} + 33}{15} = \frac{509}{140}

x = \frac{509}{140}

The solutions to the system of equations are:

x = \frac{509}{140}, y = \frac{603}{140}

x - y = 4, \frac{( x - y )}{( y + x )} = \frac{2}{5}

x + y = 50, x - 6 y = - 20

x - 2 y - 3 z + 5 s - 2 t = 4, 2 z - 6 s + 3 t = 2, 5 t = 10

3 x + 4 y + 5 = 0, y = x + 4

5 b = 2, a = 1, c = 1

What is 3x-y-3/5 =6,3y-x-2/7 =9 ?
The solution to 3x-y-3/5 =6,3y-x-2/7 =9 is x= 509/140 ,y= 603/140