What is 20x-8y=1,-8x+6y=1 ?

The solution to 20x-8y=1,-8x+6y=1 is x= 1/4 ,y= 1/2

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20x-8y=1,-8x+6y=1

20 x - 8 y = 1, - 8 x + 6 y = 1

x = \frac{1}{4}, y = \frac{1}{2}

Solution steps

[20 x - 8 y = 1 - 8 x + 6 y = 1]

Isolate

x

for

20 x - 8 y = 1 : x = \frac{1 + 8 y}{20}

Substitute

x = \frac{1 + 8 y}{20}

[- 8 \cdot \frac{1 + 8 y}{20} + 6 y = 1]

Simplify

[\frac{14 y - 2}{5} = 1]

Isolate

y

for

\frac{14 y - 2}{5} = 1 : y = \frac{1}{2}

For

x = \frac{1 + 8 y}{20}

Substitute

y = \frac{1}{2}

x = \frac{1 + 8 \cdot \frac{1}{2}}{20}

\frac{1 + 8 \cdot \frac{1}{2}}{20} = \frac{1}{4}

x = \frac{1}{4}

The solutions to the system of equations are:

x = \frac{1}{4}, y = \frac{1}{2}

- x + 5 y = 10, 2 x - 5 y = 30

1.1 x + 6 y = 7, 2 x + y = 3

5 x + 2 y = 30, 5 x - y = 15

5 x + y = 10, 5 x - 2 y = 10

y = 2 + 4 - x, y = - x