What is p(x)=3,x^3-4x^2+6x+1x=-29-192 ?

The solution to p(x)=3,x^3-4x^2+6x+1x=-29-192 is

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

p(x)=3,x^3-4x^2+6x+1x=-29-192

p (x) = 3, x^{3} - 4 x^{2} + 6 x + 1 x = - 29 - 192

(x = - 4.66294 \dots, p = 3)

Solution steps

[p = 3 x^{3} - 4 x^{2} + 6 x + 1 \cdot x = - 29 - 192]

Solve

x^{3} - 4 x^{2} + 6 x + 1 x = - 29 - 192 : x \approx - 4.66294 \dots

Plug the solutions

x = - 4.66294 \dots

into

p = 3

For

p = 3

, subsitute

x

with

- 4.66294 \dots : p = 3

Verify solutions by plugging them into the original equations

Therefore, the final solution for

p = 3, x^{3} - 4 x^{2} + 6 x + 1 x = - 29 - 192

(x = - 4.66294 \dots, p = 3)

3 x = y + 5, x + y = 11

x + y = 7, 5 x - 2 y = - 7

x + 2 y = 3, 2 x - 3 y = 13

x + y = 18, 2 x - 3 y = 150

3 x + 4 y = 1, 4 x + 2 y = - 2

What is p(x)=3,x^3-4x^2+6x+1x=-29-192 ?
The solution to p(x)=3,x^3-4x^2+6x+1x=-29-192 is