What is 10r-9a+6=7,r-6a-3=0 ?

The solution to 10r-9a+6=7,r-6a-3=0 is a=-29/51 ,r=-7/17

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10r-9a+6=7,r-6a-3=0

10 r - 9 a + 6 = 7, r - 6 a - 3 = 0

a = - \frac{29}{51}, r = - \frac{7}{17}

Solution steps

[10 r - 9 a + 6 = 7 r - 6 a - 3 = 0]

Isolate

r

for

10 r - 9 a + 6 = 7 : r = \frac{9 a + 1}{10}

Substitute

r = \frac{9 a + 1}{10}

[\frac{9 a + 1}{10} - 6 a - 3 = 0]

Simplify

[\frac{- 51 a + 1}{10} - 3 = 0]

Isolate

a

for

\frac{- 51 a + 1}{10} - 3 = 0 : a = - \frac{29}{51}

For

r = \frac{9 a + 1}{10}

Substitute

a = - \frac{29}{51}

r = \frac{9 ( - \frac{29}{51} ) + 1}{10}

\frac{9 ( - \frac{29}{51} ) + 1}{10} = - \frac{7}{17}

r = - \frac{7}{17}

The solutions to the system of equations are:

a = - \frac{29}{51}, r = - \frac{7}{17}

z = 5 - 2 i, w (z) = 6 i

\frac{x}{2} + \frac{y}{3} = \frac{1}{2}, x + \frac{y}{2} = \frac{3}{2}

x - 2 y + 3 z = 9, - x + 3 y - z = 17

2 x - 3 y = - 5, 5 x + 3 y = 19

5 x + 2 y = 19, 6 x + 5 y = 28

What is 10r-9a+6=7,r-6a-3=0 ?
The solution to 10r-9a+6=7,r-6a-3=0 is a=-29/51 ,r=-7/17