What is 5/((x-1))+1/((y-2))=2, 6/((x-1))-3/((y-2))=1 ?

The solution to 5/((x-1))+1/((y-2))=2, 6/((x-1))-3/((y-2))=1 is

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5/((x-1))+1/((y-2))=2, 6/((x-1))-3/((y-2))=1

\frac{5}{( x - 1 )} + \frac{1}{( y - 2 )} = 2, \frac{6}{( x - 1 )} - \frac{3}{( y - 2 )} = 1

(x = 4, y = 5)

Solution steps

[\frac{5}{( x - 1 )} + \frac{1}{( y - 2 )} = 2 \frac{6}{( x - 1 )} - \frac{3}{( y - 2 )} = 1]

Isolate

x

for

\frac{5}{( x - 1 )} + \frac{1}{( y - 2 )} = 2 : x = \frac{- 7 y + 15}{- 2 y + 5}; y \neq = \frac{5}{2}

Plug the solutions

x = \frac{- 7 y + 15}{- 2 y + 5}

into

\frac{6}{( x - 1 )} - \frac{3}{( y - 2 )} = 1

For

\frac{6}{( x - 1 )} - \frac{3}{( y - 2 )} = 1

, subsitute

x

with

\frac{- 7 y + 15}{- 2 y + 5} : y = 5

Plug the solutions

y = 5

into

\frac{5}{( x - 1 )} + \frac{1}{( y - 2 )} = 2

For

\frac{5}{( x - 1 )} + \frac{1}{( y - 2 )} = 2

, subsitute

y

with

5 : x = 4

Verify solutions by plugging them into the original equations

Therefore, the final solution for

\frac{5}{( x - 1 )} + \frac{1}{( y - 2 )} = 2, \frac{6}{( x - 1 )} - \frac{3}{( y - 2 )} = 1

(x = 4, y = 5)

x - y = 6, x + y = 12

5 x + y = 22, 3 x + y = 14

- 8 y + 9 x = 5, 8 y + 7 x = - 75

x + y + z = 18, 4 x + 2 y + z = 36, 6 x + 5 y + 4 z = 36

2 x - 3 y = 4, x + 5 y = 15

What is 5/((x-1))+1/((y-2))=2, 6/((x-1))-3/((y-2))=1 ?
The solution to 5/((x-1))+1/((y-2))=2, 6/((x-1))-3/((y-2))=1 is