What are the solutions to the equation -3x^2-5x+1=0 ?

The solutions to the equation -3x^2-5x+1=0 are x=-(5+sqrt(37))/6 ,x=(sqrt(37)-5)/6

Find the zeros of -3x^2-5x+1=0

The zeros of -3x^2-5x+1=0 are x=-(5+sqrt(37))/6 ,x=(sqrt(37)-5)/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 x^{2} - 5 x + 1 = 0

x = - \frac{5 + 37}{6}, x = \frac{37 - 5}{6}

Solution steps

- 3 x^{2} - 5 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 3 ) \cdot 1}{2 ( - 3 )}

(- 5)^{2} - 4 (- 3) \cdot 1 = 37

x_{1, 2} = \frac{- ( - 5 ) \pm 37}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 37}{2 ( - 3 )}, x_{2} = \frac{- ( - 5 ) - 37}{2 ( - 3 )}

x = \frac{- ( - 5 ) + 37}{2 ( - 3 )} : - \frac{5 + 37}{6}

x = \frac{- ( - 5 ) - 37}{2 ( - 3 )} : \frac{37 - 5}{6}

The solutions to the quadratic equation are:

x = - \frac{5 + 37}{6}, x = \frac{37 - 5}{6}

\frac{x - 4}{x + 5} \leq 0

\frac{x}{4} + \frac{x}{9} = 10

81 a^{2} - 64

y^{2} + 11 y + 30

w^{2} + 3 w - 10 = 0

What are the solutions to the equation -3x^2-5x+1=0 ?
The solutions to the equation -3x^2-5x+1=0 are x=-(5+sqrt(37))/6 ,x=(sqrt(37)-5)/6
Find the zeros of -3x^2-5x+1=0
The zeros of -3x^2-5x+1=0 are x=-(5+sqrt(37))/6 ,x=(sqrt(37)-5)/6