What is 4x+3y=1,8x-3y=7 ?

The solution to 4x+3y=1,8x-3y=7 is x= 2/3 ,y=-5/9

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4x+3y=1,8x-3y=7

4 x + 3 y = 1, 8 x - 3 y = 7

x = \frac{2}{3}, y = - \frac{5}{9}

Solution steps

[4 x + 3 y = 1 8 x - 3 y = 7]

Isolate

x

for

4 x + 3 y = 1 : x = \frac{1 - 3 y}{4}

Substitute

x = \frac{1 - 3 y}{4}

[8 \cdot \frac{1 - 3 y}{4} - 3 y = 7]

Simplify

[- 9 y + 2 = 7]

Isolate

y

for

- 9 y + 2 = 7 : y = - \frac{5}{9}

For

x = \frac{1 - 3 y}{4}

Substitute

y = - \frac{5}{9}

x = \frac{1 - 3 ( - \frac{5}{9} )}{4}

\frac{1 - 3 ( - \frac{5}{9} )}{4} = \frac{2}{3}

x = \frac{2}{3}

The solutions to the system of equations are:

x = \frac{2}{3}, y = - \frac{5}{9}

- 2 i w (z) = - 5 i, z = 4

5 x + 10 y = 29, 0 x + y = 35

3 x + y = 8, x + 2 y = 6

7 x + 8 y = 29, 5 x + 11 y = 26

3 (3 x + 5) = 6 x - y + 9, 12 x + 5 y = - 32