What are the solutions to the equation 4t^2-3t-3=0 ?

The solutions to the equation 4t^2-3t-3=0 are t=(3+sqrt(57))/8 ,t=(3-sqrt(57))/8

Find the zeros of 4t^2-3t-3=0

The zeros of 4t^2-3t-3=0 are t=(3+sqrt(57))/8 ,t=(3-sqrt(57))/8

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4 t^{2} - 3 t - 3 = 0

t = \frac{3 + 57}{8}, t = \frac{3 - 57}{8}

Decimal Notation

t = 1.31872 \dots, t = - 0.56872 \dots

Solution steps

4 t^{2} - 3 t - 3 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

(- 3)^{2} - 4 \cdot 4 (- 3) = 57

t_{1, 2} = \frac{- ( - 3 ) \pm 57}{2 \cdot 4}

Separate the solutions

t_{1} = \frac{- ( - 3 ) + 57}{2 \cdot 4}, t_{2} = \frac{- ( - 3 ) - 57}{2 \cdot 4}

t = \frac{- ( - 3 ) + 57}{2 \cdot 4} : \frac{3 + 57}{8}

t = \frac{- ( - 3 ) - 57}{2 \cdot 4} : \frac{3 - 57}{8}

The solutions to the quadratic equation are:

t = \frac{3 + 57}{8}, t = \frac{3 - 57}{8}

8 x < 24

∣ z - 6 ∣ \geq 3

214

\frac{4}{3} + \frac{1}{5}

5 x^{2} - 14 x + 8

What are the solutions to the equation 4t^2-3t-3=0 ?
The solutions to the equation 4t^2-3t-3=0 are t=(3+sqrt(57))/8 ,t=(3-sqrt(57))/8
Find the zeros of 4t^2-3t-3=0
The zeros of 4t^2-3t-3=0 are t=(3+sqrt(57))/8 ,t=(3-sqrt(57))/8