What is a+b+c=1,a+2b+c=2,c=1 ?

The solution to a+b+c=1,a+2b+c=2,c=1 is a=-1,b=1,c=1

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a+b+c=1,a+2b+c=2,c=1

a + b + c = 1, a + 2 b + c = 2, c = 1

a = - 1, b = 1, c = 1

Solution steps

a + b + c = 1 a + 2 b + c = 2 c = 1

Substitute

c = 1

[a + b + 1 = 1 a + 2 b + 1 = 2]

Isolate

a

for

a + b + 1 = 1 : a = - b

Substitute

a = - b

[- b + 2 b + 1 = 2]

Simplify

[b + 1 = 2]

Isolate

b

for

b + 1 = 2 : b = 1

For

a = - b

Substitute

b = 1

a = - 1

The solutions to the system of equations are:

a = - 1, b = 1, c = 1

4 x - y = 8, 3 x + 2 y = 12

3 x + 9 + 1 = 0, 2 x - 3 y + 8 = 0

- x + 6 y = 2, 7 x + y = - 29

4 x - y = 11, 5 x + 2 y = 4

6 x + 5 y = 32, 2 x + 5 y = 12

What is a+b+c=1,a+2b+c=2,c=1 ?
The solution to a+b+c=1,a+2b+c=2,c=1 is a=-1,b=1,c=1