What is the answer to 3/(7^x)=56,7^x=34 ?

The answer to 3/(7^x)=56,7^x=34 is x=-(ln(56/3))/(ln(7))

Solve for x: 3/(7^x)=56,7^x=34

The solution is x=-(ln(56/3))/(ln(7))

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\frac{3}{7 ^{x}} = 56, 7^{x} = 34

x = - \frac{ln ( \frac{56}{3} )}{ln ( 7 )}

Decimal Notation

x = - 1.50404 \dots

Solution steps

\frac{3}{7 ^{x}} = 56

Apply exponent rules

- x ln (7) = ln (\frac{56}{3})

Solve

- x ln (7) = ln (\frac{56}{3}) : x = - \frac{ln ( \frac{56}{3} )}{ln ( 7 )}

x = - \frac{ln ( \frac{56}{3} )}{ln ( 7 )}

Verify Solutions:

x = - \frac{ln ( \frac{56}{3} )}{ln ( 7 )}

True

The solution is

x = - \frac{ln ( \frac{56}{3} )}{ln ( 7 )}

3 x + 4 = 6, 2 x - 2 y = - 4

x - 2 y = 9, 3 x + y = 41

7 x + 8 = 9, - 5 x = 17

- 6 x + 6 y = 6, - x + y = 1

9 b = 200, a = 11

What is the answer to 3/(7^x)=56,7^x=34 ?
The answer to 3/(7^x)=56,7^x=34 is x=-(ln(56/3))/(ln(7))
Solve for x: 3/(7^x)=56,7^x=34
The solution is x=-(ln(56/3))/(ln(7))