What is ((3x-y))/5 =2,y-1((3x))/8-y/4 = 1/2 ?

The solution to ((3x-y))/5 =2,y-1((3x))/8-y/4 = 1/2 is x= 64/15 ,y= 14/5

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((3x-y))/5 =2,y-1((3x))/8-y/4 = 1/2

\frac{( 3 x - y )}{5} = 2, y - 1 \frac{( 3 x )}{8} - \frac{y}{4} = \frac{1}{2}

x = \frac{64}{15}, y = \frac{14}{5}

Solution steps

[\frac{( 3 x - y )}{5} = 2 y - 1 \cdot \frac{( 3 x )}{8} - \frac{y}{4} = \frac{1}{2}]

Isolate

x

for

\frac{( 3 x - y )}{5} = 2 : x = \frac{10 + y}{3}

Substitute

x = \frac{10 + y}{3}

[y - 1 \cdot \frac{3 \cdot \frac{10 + y}{3}}{8} - \frac{y}{4} = \frac{1}{2}]

Simplify

[\frac{- 10 + 5 y}{8} = \frac{1}{2}]

Isolate

y

for

\frac{- 10 + 5 y}{8} = \frac{1}{2} : y = \frac{14}{5}

For

x = \frac{10 + y}{3}

Substitute

y = \frac{14}{5}

x = \frac{10 + \frac{14}{5}}{3}

\frac{10 + \frac{14}{5}}{3} = \frac{64}{15}

x = \frac{64}{15}

The solutions to the system of equations are:

x = \frac{64}{15}, y = \frac{14}{5}

6 y - x = 6, 3 y + x = 22

3 x - 4 y = 1, 2 \cdot 8 x + 6 y = - 9

2 x - 4 y = 5, 3 x + 2 y = 8

a + 2 b = 2, 5 a - b = 4

2 x - y = 1, x + y = 0

What is ((3x-y))/5 =2,y-1((3x))/8-y/4 = 1/2 ?
The solution to ((3x-y))/5 =2,y-1((3x))/8-y/4 = 1/2 is x= 64/15 ,y= 14/5