What is 2x-y+2=4,x+y-5=0 ?

The solution to 2x-y+2=4,x+y-5=0 is x= 7/3 ,y= 8/3

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2x-y+2=4,x+y-5=0

2 x - y + 2 = 4, x + y - 5 = 0

x = \frac{7}{3}, y = \frac{8}{3}

Solution steps

[2 x - y + 2 = 4 x + y - 5 = 0]

Isolate

x

for

2 x - y + 2 = 4 : x = \frac{y + 2}{2}

Substitute

x = \frac{y + 2}{2}

[\frac{y + 2}{2} + y - 5 = 0]

Simplify

[\frac{3 y + 2}{2} - 5 = 0]

Isolate

y

for

\frac{3 y + 2}{2} - 5 = 0 : y = \frac{8}{3}

For

x = \frac{y + 2}{2}

Substitute

y = \frac{8}{3}

x = \frac{\frac{8}{3} + 2}{2}

\frac{\frac{8}{3} + 2}{2} = \frac{7}{3}

x = \frac{7}{3}

The solutions to the system of equations are:

x = \frac{7}{3}, y = \frac{8}{3}

4 x + 2 y = 46, 6 y + 2 x = 530

2 x + y = 17, 8 x - y = 83

7 x - 9 \frac{y}{2} - 2 x + \frac{4}{2} = - 15, 5 (x - 1 + y) = 25

2 + 3 y + 4 z = 7, 4 y = 2 + 5 z, 3 z - 2 x + 6 = 0

2 x + 3 y = 5, 3 x + 2 y = 7, 3 x - 2 y = 1