What is 2x+3y=7,(k-1)x+(k+1)y=3k-1 ?

The solution to 2x+3y=7,(k-1)x+(k+1)y=3k-1 is

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2x+3y=7,(k-1)x+(k+1)y=3k-1

2 x + 3 y = 7, (k - 1) x + (k + 1) y = 3 k - 1

(x = 2, y = 1)

Solution steps

[2 x + 3 y = 7 (k - 1) x + (k + 1) y = 3 k - 1]

Isolate

x

for

2 x + 3 y = 7 : x = \frac{7 - 3 y}{2}

Plug the solutions

x = \frac{7 - 3 y}{2}

into

(k - 1) x + (k + 1) y = 3 k - 1

For

(k - 1) x + (k + 1) y = 3 k - 1

, subsitute

x

with

\frac{7 - 3 y}{2} : y = 1; k \neq = 5

Plug the solutions

y = 1

into

2 x + 3 y = 7

For

2 x + 3 y = 7

, subsitute

y

with

1 : x = 2

Verify solutions by plugging them into the original equations

Therefore, the final solution for

2 x + 3 y = 7, (k - 1) x + (k + 1) y = 3 k - 1

(x = 2, y = 1)

4 x + 3 y = 8, 6 x - 4 y = - 5

x + 2 y = 7, x - 2 y = - 1

4 x + 3 y = 7, 7 x - 5 y = 43

2 x + 7 y = 3, 5 x + 4 y = - 6

2 x - 2 y = 4, x + 6 y = 0

What is 2x+3y=7,(k-1)x+(k+1)y=3k-1 ?
The solution to 2x+3y=7,(k-1)x+(k+1)y=3k-1 is