What are the solutions to the equation (x^2-4x+5)=0 ?

The solutions to the equation (x^2-4x+5)=0 are x=2+i,x=2-i

Find the zeros of (x^2-4x+5)=0

The zeros of (x^2-4x+5)=0 are x=2+i,x=2-i

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(x^{2} - 4 x + 5) = 0

x = 2 + i, x = 2 - i

Solution steps

(x^{2} - 4 x + 5) = 0

Refine

x^{2} - 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 5 : 2 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 i}{2 \cdot 1} : 2 + i

x = \frac{- ( - 4 ) - 2 i}{2 \cdot 1} : 2 - i

The solutions to the quadratic equation are:

x = 2 + i, x = 2 - i

6 h^{2} + 8 h + 2 = 0

- 11 + \frac{n}{- 8} = - 13

x - 3 < 2 x + 1 < 5

x^{2} = 6 - 5 x

25 - 9

What are the solutions to the equation (x^2-4x+5)=0 ?
The solutions to the equation (x^2-4x+5)=0 are x=2+i,x=2-i
Find the zeros of (x^2-4x+5)=0
The zeros of (x^2-4x+5)=0 are x=2+i,x=2-i