What is 3x-4(y-2)=2,2x+3(y-3)=4 ?

The solution to 3x-4(y-2)=2,2x+3(y-3)=4 is x=2,y=3

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3x-4(y-2)=2,2x+3(y-3)=4

3 x - 4 (y - 2) = 2, 2 x + 3 (y - 3) = 4

x = 2, y = 3

Solution steps

[3 x - 4 (y - 2) = 2 2 x + 3 (y - 3) = 4]

Isolate

x

for

3 x - 4 (y - 2) = 2 : x = \frac{4 y - 6}{3}

Substitute

x = \frac{4 y - 6}{3}

[2 \cdot \frac{4 y - 6}{3} + 3 (y - 3) = 4]

Simplify

[\frac{17 y - 12}{3} - 9 = 4]

Isolate

y

for

\frac{17 y - 12}{3} - 9 = 4 : y = 3

For

x = \frac{4 y - 6}{3}

Substitute

y = 3

x = \frac{4 \cdot 3 - 6}{3}

\frac{4 \cdot 3 - 6}{3} = 2

x = 2

The solutions to the system of equations are:

x = 2, y = 3

d_{1} = 49.5 \cdot 34 h, d_{1} = 148.6

x + y = 7, 2 x + 5 y = 32

a = - 1, 2 b = 3, c = 1

\frac{2}{x} + \frac{3}{y} = 5, \frac{3}{x} - \frac{1}{y} = - 9

3 x + 4 y = - 6, 2 x + 4 y = 16

What is 3x-4(y-2)=2,2x+3(y-3)=4 ?
The solution to 3x-4(y-2)=2,2x+3(y-3)=4 is x=2,y=3