What is 3y-4z=8,2y-z=9 ?

The solution to 3y-4z=8,2y-z=9 is y= 28/5 ,z= 11/5

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3y-4z=8,2y-z=9

3 y - 4 z = 8, 2 y - z = 9

y = \frac{28}{5}, z = \frac{11}{5}

Solution steps

[3 y - 4 z = 8 2 y - z = 9]

Isolate

y

for

3 y - 4 z = 8 : y = \frac{8 + 4 z}{3}

Substitute

y = \frac{8 + 4 z}{3}

[2 \cdot \frac{8 + 4 z}{3} - z = 9]

Simplify

[\frac{16 + 5 z}{3} = 9]

Isolate

z

for

\frac{16 + 5 z}{3} = 9 : z = \frac{11}{5}

For

y = \frac{8 + 4 z}{3}

Substitute

z = \frac{11}{5}

y = \frac{8 + 4 \cdot \frac{11}{5}}{3}

\frac{8 + 4 \cdot \frac{11}{5}}{3} = \frac{28}{5}

y = \frac{28}{5}

The solutions to the system of equations are:

y = \frac{28}{5}, z = \frac{11}{5}

a = - 1, \frac{3}{15} b = - 2, \frac{0}{26} c = - \frac{7}{10}

x - y = 3, \frac{x}{3} + \frac{y}{2} = 6

x = t + 1, y = 3 t + 2

3 x + 2 y = 18, 3 x + y = 12

x + 2 y = 5, 3 \frac{x}{2} + 3 y = 10