What is 2x-3y-3=0,((2x))/3+4y+1/2 =0 ?

The solution to 2x-3y-3=0,((2x))/3+4y+1/2 =0 is x= 21/20 ,y=-3/10

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2x-3y-3=0,((2x))/3+4y+1/2 =0

2 x - 3 y - 3 = 0, \frac{( 2 x )}{3} + 4 y + \frac{1}{2} = 0

x = \frac{21}{20}, y = - \frac{3}{10}

Solution steps

[2 x - 3 y - 3 = 0 \frac{( 2 x )}{3} + 4 y + \frac{1}{2} = 0]

Isolate

x

for

2 x - 3 y - 3 = 0 : x = \frac{3 y + 3}{2}

Substitute

x = \frac{3 y + 3}{2}

[\frac{2 \cdot \frac{3 y + 3}{2}}{3} + 4 y + \frac{1}{2} = 0]

Simplify

[5 y + \frac{3}{2} = 0]

Isolate

y

for

5 y + \frac{3}{2} = 0 : y = - \frac{3}{10}

For

x = \frac{3 y + 3}{2}

Substitute

y = - \frac{3}{10}

x = \frac{3 ( - \frac{3}{10} ) + 3}{2}

\frac{3 ( - \frac{3}{10} ) + 3}{2} = \frac{21}{20}

x = \frac{21}{20}

The solutions to the system of equations are:

x = \frac{21}{20}, y = - \frac{3}{10}

2 x - 3 y = 0, 3 x - 8 y = 0

y = 7 x, x + y = 8

15 x + 17 y = 21, 17 x + 15 y = 17

4 x + 3 y = 32, 2 x - 7 y = - 18

3 x + 7 y = 35, 8 x - 7 y = - 35

What is 2x-3y-3=0,((2x))/3+4y+1/2 =0 ?
The solution to 2x-3y-3=0,((2x))/3+4y+1/2 =0 is x= 21/20 ,y=-3/10