What is 20d+30b=19,35d+40b=295 ?

The solution to 20d+30b=19,35d+40b=295 is b=-1047/50 ,d= 809/25

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20d+30b=19,35d+40b=295

20 d + 30 b = 19, 35 d + 40 b = 295

b = - \frac{1047}{50}, d = \frac{809}{25}

Solution steps

[20 d + 30 b = 19 35 d + 40 b = 295]

Isolate

d

for

20 d + 30 b = 19 : d = \frac{19 - 30 b}{20}

Substitute

d = \frac{19 - 30 b}{20}

[35 \cdot \frac{19 - 30 b}{20} + 40 b = 295]

Simplify

[\frac{- 50 b + 133}{4} = 295]

Isolate

b

for

\frac{- 50 b + 133}{4} = 295 : b = - \frac{1047}{50}

For

d = \frac{19 - 30 b}{20}

Substitute

b = - \frac{1047}{50}

d = \frac{19 - 30 ( - \frac{1047}{50} )}{20}

\frac{19 - 30 ( - \frac{1047}{50} )}{20} = \frac{809}{25}

d = \frac{809}{25}

The solutions to the system of equations are:

b = - \frac{1047}{50}, d = \frac{809}{25}

3 x - y = 7, 2 x + 3 y = 12

3 x + y = 1, 2.5 x - 2 y = 7

(2) 2 x + y = 7, x - 2 y = 6

2 x + 3 y = 16, 4 x + 2 y = 24

x - \frac{3}{5} \cdot y = \frac{66}{5}, \frac{1}{10} \cdot x + \frac{3}{4} \cdot y = - \frac{87}{20}

What is 20d+30b=19,35d+40b=295 ?
The solution to 20d+30b=19,35d+40b=295 is b=-1047/50 ,d= 809/25