What is 7y+10x-8=2,y-5x-18=0 ?

The solution to 7y+10x-8=2,y-5x-18=0 is x=-116/45 ,y= 46/9

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7y+10x-8=2,y-5x-18=0

7 y + 10 x - 8 = 2, y - 5 x - 18 = 0

x = - \frac{116}{45}, y = \frac{46}{9}

Solution steps

[7 y + 10 x - 8 = 2 y - 5 x - 18 = 0]

Isolate

y

for

7 y + 10 x - 8 = 2 : y = \frac{- 10 x + 10}{7}

Substitute

y = \frac{- 10 x + 10}{7}

[\frac{- 10 x + 10}{7} - 5 x - 18 = 0]

Simplify

[\frac{- 45 x + 10}{7} - 18 = 0]

Isolate

x

for

\frac{- 45 x + 10}{7} - 18 = 0 : x = - \frac{116}{45}

For

y = \frac{- 10 x + 10}{7}

Substitute

x = - \frac{116}{45}

y = \frac{- 10 ( - \frac{116}{45} ) + 10}{7}

\frac{- 10 ( - \frac{116}{45} ) + 10}{7} = \frac{46}{9}

y = \frac{46}{9}

The solutions to the system of equations are:

x = - \frac{116}{45}, y = \frac{46}{9}

2 x + y = 4, 2 x - 2 y = 10

3 x + 2 y = - 9, 5 x - y = - 2

\frac{( 3 x )}{2} - \frac{( 5 y )}{3} = - 2, \frac{x}{3} + \frac{y}{2} = \frac{13}{6}

7 x - 4 y = 9, 4 y = 15

3 x + 2 y = 8, 5 x - 3 y = 7

What is 7y+10x-8=2,y-5x-18=0 ?
The solution to 7y+10x-8=2,y-5x-18=0 is x=-116/45 ,y= 46/9