What are the solutions to the equation 7v^2-8v-8=0 ?

The solutions to the equation 7v^2-8v-8=0 are v=(2(2+3sqrt(2)))/7 ,v=(2(2-3sqrt(2)))/7

Find the zeros of 7v^2-8v-8=0

The zeros of 7v^2-8v-8=0 are v=(2(2+3sqrt(2)))/7 ,v=(2(2-3sqrt(2)))/7

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7 v^{2} - 8 v - 8 = 0

v = \frac{2 ( 2 + 3 2 )}{7}, v = \frac{2 ( 2 - 3 2 )}{7}

Decimal Notation

v = 1.78361 \dots, v = - 0.64075 \dots

Solution steps

7 v^{2} - 8 v - 8 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 7 ( - 8 )}{2 \cdot 7}

(- 8)^{2} - 4 \cdot 7 (- 8) = 122

v_{1, 2} = \frac{- ( - 8 ) \pm 12 2}{2 \cdot 7}

Separate the solutions

v_{1} = \frac{- ( - 8 ) + 12 2}{2 \cdot 7}, v_{2} = \frac{- ( - 8 ) - 12 2}{2 \cdot 7}

v = \frac{- ( - 8 ) + 12 2}{2 \cdot 7} : \frac{2 ( 2 + 3 2 )}{7}

v = \frac{- ( - 8 ) - 12 2}{2 \cdot 7} : \frac{2 ( 2 - 3 2 )}{7}

The solutions to the quadratic equation are:

v = \frac{2 ( 2 + 3 2 )}{7}, v = \frac{2 ( 2 - 3 2 )}{7}

- 2 + 6 x > 34

13 - 4 < 8

(3 + i)^{6}

\frac{3}{4} x^{2} = 12

4 + \frac{1}{3} r = r - 8

What are the solutions to the equation 7v^2-8v-8=0 ?
The solutions to the equation 7v^2-8v-8=0 are v=(2(2+3sqrt(2)))/7 ,v=(2(2-3sqrt(2)))/7
Find the zeros of 7v^2-8v-8=0
The zeros of 7v^2-8v-8=0 are v=(2(2+3sqrt(2)))/7 ,v=(2(2-3sqrt(2)))/7