What is 2x-8y+3z=1,-x+2y-3z=-2 ?

The solution to 2x-8y+3z=1,-x+2y-3z=-2 is x=(-9z+7)/2 ,y=-(3z-3)/4

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2x-8y+3z=1,-x+2y-3z=-2

2 x - 8 y + 3 z = 1, - x + 2 y - 3 z = - 2

x = \frac{- 9 z + 7}{2}, y = - \frac{3 z - 3}{4}

Solution steps

[2 x - 8 y + 3 z = 1 - x + 2 y - 3 z = - 2]

Isolate

x

for

2 x - 8 y + 3 z = 1 : x = \frac{1 + 8 y - 3 z}{2}

Substitute

x = \frac{1 + 8 y - 3 z}{2}

[- \frac{1 + 8 y - 3 z}{2} + 2 y - 3 z = - 2]

Simplify

[\frac{- 4 y - 3 z - 1}{2} = - 2]

Isolate

y

for

\frac{- 4 y - 3 z - 1}{2} = - 2 : y = - \frac{3 z - 3}{4}

For

x = \frac{1 + 8 y - 3 z}{2}

Expressing

x

in terms of

z

x = \frac{1 + 8 ( - \frac{3 z - 3}{4} ) - 3 z}{2}

Simplify

\frac{1 + 8 ( - \frac{3 z - 3}{4} ) - 3 z}{2} : \frac{- 9 z + 7}{2}

x = \frac{- 9 z + 7}{2}

The solutions to the system of equations are:

x = \frac{- 9 z + 7}{2}, y = - \frac{3 z - 3}{4}

x + y = 2, x - y = - 6

x - 10 y = 2, y = 4

x - y = 4, x + y = 8

- 2 x - 3 y = 1, 6 y + 4 x = - 2

3 x - 2 y = 13, 4 x + 3 y = 23

What is 2x-8y+3z=1,-x+2y-3z=-2 ?
The solution to 2x-8y+3z=1,-x+2y-3z=-2 is x=(-9z+7)/2 ,y=-(3z-3)/4