What is x+y-z=1,z+x-y=3,z-x+y=7 ?

The solution to x+y-z=1,z+x-y=3,z-x+y=7 is x=2,y=4,z=5

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x+y-z=1,z+x-y=3,z-x+y=7

x + y - z = 1, z + x - y = 3, z - x + y = 7

x = 2, y = 4, z = 5

Solution steps

x + y - z = 1 z + x - y = 3 z - x + y = 7

Isolate

x

for

x + y - z = 1 : x = 1 - y + z

Substitute

x = 1 - y + z

[z + 1 - y + z - y = 3 z - (1 - y + z) + y = 7]

Simplify

[- 2 y + 2 z + 1 = 3 2 y - 1 = 7]

Isolate

y

for

2 y - 1 = 7 : y = 4

Substitute

y = 4

[- 2 \cdot 4 + 2 z + 1 = 3]

Simplify

[2 z - 7 = 3]

Isolate

z

for

2 z - 7 = 3 : z = 5

For

x = 1 - y + z

Substitute

y = 4, z = 5

x = 1 - 4 + 5

Simplify

x = 2

The solutions to the system of equations are:

x = 2, y = 4, z = 5

4 x - 3 y = 9, 3 x - 4 y = 5

8 x - 5 y + 40 = 7, x - 2 y = 0

\frac{7}{x} - \frac{15}{y} = 9, \cdot \frac{11}{x} - \frac{8}{y} = - 17

5 x - 2 y = 7, 4 x + 3 y = - 2

3 x - 18 y = - 54, 5 x - 4 y = - 40

What is x+y-z=1,z+x-y=3,z-x+y=7 ?
The solution to x+y-z=1,z+x-y=3,z-x+y=7 is x=2,y=4,z=5