What is x/3+y=16,3x+y/2 = 61/2 ?

The solution to x/3+y=16,3x+y/2 = 61/2 is x= 135/17 ,y= 227/17

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x/3+y=16,3x+y/2 = 61/2

\frac{x}{3} + y = 16, 3 x + \frac{y}{2} = \frac{61}{2}

x = \frac{135}{17}, y = \frac{227}{17}

Solution steps

[\frac{x}{3} + y = 16 3 x + \frac{y}{2} = \frac{61}{2}]

Isolate

x

for

\frac{x}{3} + y = 16 : x = 48 - 3 y

Substitute

x = 48 - 3 y

[3 (48 - 3 y) + \frac{y}{2} = \frac{61}{2}]

Simplify

[- \frac{17 y}{2} + 144 = \frac{61}{2}]

Isolate

y

for

- \frac{17 y}{2} + 144 = \frac{61}{2} : y = \frac{227}{17}

For

x = 48 - 3 y

Substitute

y = \frac{227}{17}

x = 48 - 3 \cdot \frac{227}{17}

48 - 3 \cdot \frac{227}{17} = \frac{135}{17}

x = \frac{135}{17}

The solutions to the system of equations are:

x = \frac{135}{17}, y = \frac{227}{17}

2 x + 4 y = 22, 2 x + 2 y = 15

3 x + 4 y = 2, 9 x + 16 y = 7

2 x + 3 y = 7, 5 x - y = 9

15 x + 3 y = 15, 12 x + 4 y = 20

x - y = 3, 2 x - 3 y = 1

What is x/3+y=16,3x+y/2 = 61/2 ?
The solution to x/3+y=16,3x+y/2 = 61/2 is x= 135/17 ,y= 227/17