What is 4x-y=0,3x+2y=12 ?

The solution to 4x-y=0,3x+2y=12 is x= 12/11 ,y= 48/11

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4x-y=0,3x+2y=12

4 x - y = 0, 3 x + 2 y = 12

x = \frac{12}{11}, y = \frac{48}{11}

Solution steps

[4 x - y = 0 3 x + 2 y = 12]

Isolate

x

for

4 x - y = 0 : x = \frac{y}{4}

Substitute

x = \frac{y}{4}

[3 \cdot \frac{y}{4} + 2 y = 12]

Simplify

[\frac{11 y}{4} = 12]

Isolate

y

for

\frac{11 y}{4} = 12 : y = \frac{48}{11}

For

x = \frac{y}{4}

Substitute

y = \frac{48}{11}

x = \frac{\frac{48}{11}}{4}

\frac{\frac{48}{11}}{4} = \frac{12}{11}

x = \frac{12}{11}

The solutions to the system of equations are:

x = \frac{12}{11}, y = \frac{48}{11}

\frac{x}{3} + y = 1, 2 x - 2 y = 0

x + 3 y = - 18, 4 x - y = - 7

4 x + 3 y = 11, 3 x + 4 y = 10

x + y = 6, x = y + 2

a = 4, b = 5, c = 6