What is 23x+29y=98,29x-23y=110 ?

The solution to 23x+29y=98,29x-23y=110 is x= 2722/685 ,y= 156/685

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23x+29y=98,29x-23y=110

23 x + 29 y = 98, 29 x - 23 y = 110

x = \frac{2722}{685}, y = \frac{156}{685}

Solution steps

[23 x + 29 y = 98 29 x - 23 y = 110]

Isolate

x

for

23 x + 29 y = 98 : x = \frac{98 - 29 y}{23}

Substitute

x = \frac{98 - 29 y}{23}

[29 \cdot \frac{98 - 29 y}{23} - 23 y = 110]

Simplify

[\frac{2842 - 1370 y}{23} = 110]

Isolate

y

for

\frac{2842 - 1370 y}{23} = 110 : y = \frac{156}{685}

For

x = \frac{98 - 29 y}{23}

Substitute

y = \frac{156}{685}

x = \frac{98 - 29 \cdot \frac{156}{685}}{23}

\frac{98 - 29 \cdot \frac{156}{685}}{23} = \frac{2722}{685}

x = \frac{2722}{685}

The solutions to the system of equations are:

x = \frac{2722}{685}, y = \frac{156}{685}

2 x + 3 y + 5 = 0, 3 x - 2 y - 12 = 0

8 x + y = - 16, - 3 x + y = - 5

x + 3 y = 17, x + 2 y = 12

10 x - (4 a + 4 b) x = 5, a + b = 13

4 x - 5 y - 11 z = 1, 2 x - 3 y + z = 1, 2 x + 3 y - 5 z = 2

What is 23x+29y=98,29x-23y=110 ?
The solution to 23x+29y=98,29x-23y=110 is x= 2722/685 ,y= 156/685