What is x+y+z=11,0x+2y+3z=25,4x+5y+7z=800 ?

The solution to x+y+z=11,0x+2y+3z=25,4x+5y+7z=800 is x= 739/3 ,y=-731,z= 1487/3

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x+y+z=11,0x+2y+3z=25,4x+5y+7z=800

x + y + z = 11, 0 x + 2 y + 3 z = 25, 4 x + 5 y + 7 z = 800

x = \frac{739}{3}, y = - 731, z = \frac{1487}{3}

Solution steps

x + y + z = 11 0 \cdot x + 2 y + 3 z = 25 4 x + 5 y + 7 z = 800

Isolate

x

for

x + y + z = 11 : x = 11 - y - z

Substitute

x = 11 - y - z

[0 \cdot (11 - y - z) + 2 y + 3 z = 25 4 (11 - y - z) + 5 y + 7 z = 800]

Simplify

[2 y + 3 z = 25 y + 3 z + 44 = 800]

Isolate

y

for

2 y + 3 z = 25 : y = \frac{25 - 3 z}{2}

Substitute

y = \frac{25 - 3 z}{2}

[\frac{25 - 3 z}{2} + 3 z + 44 = 800]

Simplify

[\frac{25 + 3 z}{2} + 44 = 800]

Isolate

z

for

\frac{25 + 3 z}{2} + 44 = 800 : z = \frac{1487}{3}

For

y = \frac{25 - 3 z}{2}

Substitute

z = \frac{1487}{3}

y = \frac{25 - 3 \cdot \frac{1487}{3}}{2}

\frac{25 - 3 \cdot \frac{1487}{3}}{2} = - 731

y = - 731

For

x = 11 - y - z

Substitute

y = - 731, z = \frac{1487}{3}

x = 11 - (- 731) - \frac{1487}{3}

11 - (- 731) - \frac{1487}{3} = \frac{739}{3}

x = \frac{739}{3}

The solutions to the system of equations are:

x = \frac{739}{3}, y = - 731, z = \frac{1487}{3}

x + y = 55, 2 x + 4 y = 170

y = 11, x = 2

5 x - 2 y = 7, 7 x - 5 y = 4

3 x - 2 y = 16, 2 x + 3 y = 41

a (x) = (b - 5) x + 2, b (x) = 3 x + 2 b

What is x+y+z=11,0x+2y+3z=25,4x+5y+7z=800 ?
The solution to x+y+z=11,0x+2y+3z=25,4x+5y+7z=800 is x= 739/3 ,y=-731,z= 1487/3