What is 2/x+2/y = 1/6 , 3/x+2/y =0 ?

The solution to 2/x+2/y = 1/6 , 3/x+2/y =0 is

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2/x+2/y = 1/6 , 3/x+2/y =0

\frac{2}{x} + \frac{2}{y} = \frac{1}{6}, \frac{3}{x} + \frac{2}{y} = 0

(x = - 6, y = 4)

Solution steps

[\frac{2}{x} + \frac{2}{y} = \frac{1}{6} \frac{3}{x} + \frac{2}{y} = 0]

Subtract the equations

\frac{2}{x} + \frac{2}{y} = \frac{1}{6}

\frac{2}{x} + \frac{2}{y} - (\frac{3}{x} + \frac{2}{y}) = \frac{1}{6} - 0

Simplify

- \frac{1}{x} = \frac{1}{6}

Solve

- \frac{1}{x} = \frac{1}{6} : x = - 6

Plug the solutions

x = - 6

into

\frac{2}{x} + \frac{2}{y} = \frac{1}{6}

For

\frac{2}{x} + \frac{2}{y} = \frac{1}{6}

, subsitute

x

with

- 6 : y = 4

Verify solutions by plugging them into the original equations

Therefore, the final solution for

\frac{2}{x} + \frac{2}{y} = \frac{1}{6}, \frac{3}{x} + \frac{2}{y} = 0

(x = - 6, y = 4)

3 x + y = - 1, x - y = 5

b = - 5, a = 1

2 x + y - 6 = 4, x - 2 y - 4 = 0

11 x - 8 y = 27, 3 x + 5 y = - 7

y = \frac{1}{4} x^{4} - 2, x^{0} = - 1

What is 2/x+2/y = 1/6 , 3/x+2/y =0 ?
The solution to 2/x+2/y = 1/6 , 3/x+2/y =0 is