What are the solutions to the equation -12x^2+12x=0 ?

The solutions to the equation -12x^2+12x=0 are x=0,x=1

Find the zeros of -12x^2+12x=0

The zeros of -12x^2+12x=0 are x=0,x=1

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- 12 x^{2} + 12 x = 0

x = 0, x = 1

Solution steps

- 12 x^{2} + 12 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 12 ) \cdot 0}{2 ( - 12 )}

1 2^{2} - 4 (- 12) \cdot 0 = 12

x_{1, 2} = \frac{- 12 \pm 12}{2 ( - 12 )}

Separate the solutions

x_{1} = \frac{- 12 + 12}{2 ( - 12 )}, x_{2} = \frac{- 12 - 12}{2 ( - 12 )}

x = \frac{- 12 + 12}{2 ( - 12 )} : 0

x = \frac{- 12 - 12}{2 ( - 12 )} : 1

The solutions to the quadratic equation are:

x = 0, x = 1

36 x^{2} + 16 x + 2 = 0

- \frac{4}{- 4}

15 r^{2} - 6 r - 3 = - 2 r

∣ 4 x - 8 ∣ > 5

7 + 2 x - x^{2} = 0

What are the solutions to the equation -12x^2+12x=0 ?
The solutions to the equation -12x^2+12x=0 are x=0,x=1
Find the zeros of -12x^2+12x=0
The zeros of -12x^2+12x=0 are x=0,x=1