What is 2p+3q-4=3,p-2q-19=0 ?

The solution to 2p+3q-4=3,p-2q-19=0 is p= 71/7 ,q=-31/7

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2p+3q-4=3,p-2q-19=0

2 p + 3 q - 4 = 3, p - 2 q - 19 = 0

p = \frac{71}{7}, q = - \frac{31}{7}

Solution steps

[2 p + 3 q - 4 = 3 p - 2 q - 19 = 0]

Isolate

p

for

2 p + 3 q - 4 = 3 : p = \frac{- 3 q + 7}{2}

Substitute

p = \frac{- 3 q + 7}{2}

[\frac{- 3 q + 7}{2} - 2 q - 19 = 0]

Simplify

[\frac{- 7 q + 7}{2} - 19 = 0]

Isolate

q

for

\frac{- 7 q + 7}{2} - 19 = 0 : q = - \frac{31}{7}

For

p = \frac{- 3 q + 7}{2}

Substitute

q = - \frac{31}{7}

p = \frac{- 3 ( - \frac{31}{7} ) + 7}{2}

\frac{- 3 ( - \frac{31}{7} ) + 7}{2} = \frac{71}{7}

p = \frac{71}{7}

The solutions to the system of equations are:

p = \frac{71}{7}, q = - \frac{31}{7}

x - 4 y = 2, 3 x + y = 1

(i) 2 x - y = - 2, x + 5 y = 5

2 x - 5 y = - 7, 3 x = 18 - 2 y

2 x + 3 y = 8, 5 x - 6 y = 10

x + y = 7, y + 2 = 9, 2 + x = 8

What is 2p+3q-4=3,p-2q-19=0 ?
The solution to 2p+3q-4=3,p-2q-19=0 is p= 71/7 ,q=-31/7