What is x+y-2z=9,2x-y+4z=4,2x-y+6z=-1 ?

The solution to x+y-2z=9,2x-y+4z=4,2x-y+6z=-1 is x=6,y=-2,z=-5/2

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x+y-2z=9,2x-y+4z=4,2x-y+6z=-1

x + y - 2 z = 9, 2 x - y + 4 z = 4, 2 x - y + 6 z = - 1

x = 6, y = - 2, z = - \frac{5}{2}

Solution steps

x + y - 2 z = 9 2 x - y + 4 z = 4 2 x - y + 6 z = - 1

Isolate

x

for

x + y - 2 z = 9 : x = 9 - y + 2 z

Substitute

x = 9 - y + 2 z

[2 (9 - y + 2 z) - y + 4 z = 4 2 (9 - y + 2 z) - y + 6 z = - 1]

Simplify

[- 3 y + 8 z + 18 = 4 - 3 y + 10 z + 18 = - 1]

Isolate

y

for

- 3 y + 8 z + 18 = 4 : y = - \frac{- 8 z - 14}{3}

Substitute

y = - \frac{- 8 z - 14}{3}

[- 3 (- \frac{- 8 z - 14}{3}) + 10 z + 18 = - 1]

Simplify

[2 z + 4 = - 1]

Isolate

z

for

2 z + 4 = - 1 : z = - \frac{5}{2}

For

y = - \frac{- 8 z - 14}{3}

Substitute

z = - \frac{5}{2}

y = - \frac{- 8 ( - \frac{5}{2} ) - 14}{3}

- \frac{- 8 ( - \frac{5}{2} ) - 14}{3} = - 2

y = - 2

For

x = 9 - y + 2 z

Substitute

y = - 2, z = - \frac{5}{2}

x = 9 - (- 2) + 2 (- \frac{5}{2})

9 - (- 2) + 2 (- \frac{5}{2}) = 6

x = 6

The solutions to the system of equations are:

x = 6, y = - 2, z = - \frac{5}{2}

x = y, x = 0, y = 3

3 x - y - 4 = 0, 4 x + y - 17 = 0

- 4 x - 4 y = 24, 4 x - 5 y = 39

- 2 x + 5 y = 2, 8 - 4 x + 6 y = - 48

x + y = 4, 2 x - 5 y = 1

What is x+y-2z=9,2x-y+4z=4,2x-y+6z=-1 ?
The solution to x+y-2z=9,2x-y+4z=4,2x-y+6z=-1 is x=6,y=-2,z=-5/2