What is 4x+y=3,4x+4y=16 ?

The solution to 4x+y=3,4x+4y=16 is x=-1/3 ,y= 13/3

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4x+y=3,4x+4y=16

4 x + y = 3, 4 x + 4 y = 16

x = - \frac{1}{3}, y = \frac{13}{3}

Solution steps

[4 x + y = 3 4 x + 4 y = 16]

Isolate

x

for

4 x + y = 3 : x = \frac{3 - y}{4}

Substitute

x = \frac{3 - y}{4}

[4 \cdot \frac{3 - y}{4} + 4 y = 16]

Simplify

[3 + 3 y = 16]

Isolate

y

for

3 + 3 y = 16 : y = \frac{13}{3}

For

x = \frac{3 - y}{4}

Substitute

y = \frac{13}{3}

x = \frac{3 - \frac{13}{3}}{4}

\frac{3 - \frac{13}{3}}{4} = - \frac{1}{3}

x = - \frac{1}{3}

The solutions to the system of equations are:

x = - \frac{1}{3}, y = \frac{13}{3}

x = 5 y + 8, - 7 x + 8 y = 25

5 x + 6 y = 12, 3 x + 5 y = 21

2 x + 3 y = 4, - 3 x + 2 y = 1

\frac{2}{x} + \frac{3}{y} = \frac{9}{( x y )}, \frac{4}{x} + \frac{9}{y} = \frac{21}{( x y )}

5 x + 2 y = 2, 2 - 2 x + 6 y = 3