What are the solutions to the equation 2x^2+11x-4=2 ?

The solutions to the equation 2x^2+11x-4=2 are x= 1/2 ,x=-6

Find the zeros of 2x^2+11x-4=2

The zeros of 2x^2+11x-4=2 are x= 1/2 ,x=-6

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2 x^{2} + 11 x - 4 = 2

x = \frac{1}{2}, x = - 6

Solution steps

2 x^{2} + 11 x - 4 = 2

Move

2

to the left side

2 x^{2} + 11 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

1 1^{2} - 4 \cdot 2 (- 6) = 13

x_{1, 2} = \frac{- 11 \pm 13}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 11 + 13}{2 \cdot 2}, x_{2} = \frac{- 11 - 13}{2 \cdot 2}

x = \frac{- 11 + 13}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 11 - 13}{2 \cdot 2} : - 6

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 6

0.25 x + 35 = 0.15 x + 50

x + 1 = - 5

x^{4} + 14 x^{2} + 45

4 ∣ x + 2 ∣ - 10 \geq - 6

\frac{2 x + 10}{x + 3} \geq 1

What are the solutions to the equation 2x^2+11x-4=2 ?
The solutions to the equation 2x^2+11x-4=2 are x= 1/2 ,x=-6
Find the zeros of 2x^2+11x-4=2
The zeros of 2x^2+11x-4=2 are x= 1/2 ,x=-6