What is 8er=4,a^{25}=23 ?

The solution to 8er=4,a^{25}=23 is

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8er=4,a^{25}=23

8 er = 4, a^{25} = 23

Solution steps

[8 er = 4 a^{25} = 23]

Solve

8 er = 4 : r = \frac{1}{2 e}

For

a^{25} = 23

, subsitute

r

with

\frac{1}{2 e}

a^{25} = 23

Solve

For

8 er = 4

, subsitute

a

with

8 er = 4

8 er = 4 : r = \frac{1}{2 e}

Verify solutions by plugging them into the original equations

Therefore, the final solution for

8 er = 4, a^{25} = 23

(k - 1) x + 3 y = 7, (k + 1) x + 6 y = 5 k - 1

x + y = 6, 3 x - y = 14

x + 2 y = 2, 6 x = 7 - y

x - 3 y = 9, 2 y + x = 4

4 x - 3 y = 18, 2 x + 5 y = - 4