What is (v)-5y-16=3,x+4y-1=0 ?

The solution to (v)-5y-16=3,x+4y-1=0 is v=5y+19,x=-4y+1

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(v)-5y-16=3,x+4y-1=0

(v) - 5 y - 16 = 3, x + 4 y - 1 = 0

v = 5 y + 19, x = - 4 y + 1

Solution steps

[(v) - 5 y - 16 = 3 x + 4 y - 1 = 0]

Isolate

v

for

(v) - 5 y - 16 = 3 : v = 5 y + 19

[x + 4 y - 1 = 0]

Isolate

x

for

x + 4 y - 1 = 0 : x = - 4 y + 1

Expressing

v

in terms of

y

v = 5 y + 19

The solutions to the system of equations are:

v = 5 y + 19, x = - 4 y + 1

2 x - y = 3, x + y = 3

f (x) = 2, 7 f (x) = 3 x - 9

2 x + 3 y = 51, 1 x - 5 y = 6

\frac{5}{3} y = \frac{34}{3}, x = 2

\frac{11}{3} \cdot x + \frac{3}{4} \cdot y = \frac{5}{12}, \frac{7}{6} \cdot x + \frac{1}{5} \cdot y - \frac{5}{30} = 0

What is (v)-5y-16=3,x+4y-1=0 ?
The solution to (v)-5y-16=3,x+4y-1=0 is v=5y+19,x=-4y+1